Marc Reid
@reid-indeed.bsky.social did:plc:x3rx2igghmtw7s4hov243cti
🧪 Senior Lecturer | U. of Strathclyde 📕 Author | “You Are Not a Fraud” 🎤 Host | The reid_indeed Podcast 🎥 CSO | Kineticolor Ltd https://www.dr-marc-reid.com https://www.kineticolor.org
En Bluesky desde el
- Seguidores
- 532
- Siguiendo
- 911
- Posts
- 58
- Días en rankings
- 0
Resumen
Marc Reid (@reid-indeed.bsky.social) es un usuario de Bluesky que se unió el 18 enero 2025. Tiene 532 seguidores, sigue a 911 cuentas y ha publicado 58 posts.
Apariciones en rankings
Los mejores días en que los posts de esta cuenta entraron en la lista diaria de Debya.
Esta cuenta aún no ha aparecido en un ranking diario.
Posts que le gustaron recientemente
Me gusta públicos de la red Bluesky.
As both an academic and a writer, I am repelled by the "this looks like a long document. Would you like me to summarize it for you?" that seems to appear at the top of every pdf viewer now. NO. The *entire point* of good writing (either books or journal papers) is that every sentence has a purpose.
Ver postHearing these two amazing actors reading my book - bringing it to life! - is so wonderful! Pippa Bennet-Warner (who has starred in so many roles - Doctor Who, Gangs of London, Elden Ring) & Harry Lloyd (Robin Hood, Doctor Who and GoT - as Viserys Targaryen - as well as Viktor in Arcane!) Sound up!
Ver postWhat challenges is digital chemistry facing when it comes to accurately monitoring reactions with standard digital cameras – and how can research navigate these? Hugh Ryan reports: @rsc.org @chemicalscience.rsc.org #ChemSky www.chemistryworld.com/news/molecul...
Ver postThis is awesome! I guess this works with sets of photos? We have a lot of photos of fluorescent nanoparticle suspensions, and I have done rough kinetics analyzing the colour with homemade Octave scripts, but it's still far from optimal
Ver postFingers crossed for the bumblebees 🐝, this could become a cherry 🍒 summer 🌞!
Ver post
Cuentas que bloquea
En Bluesky los bloqueos son registros públicos.
Esta cuenta no bloquea a nadie.